(3/2)t^2-11t+14=0

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Solution for (3/2)t^2-11t+14=0 equation: 



(3/2)t^2-11t+14=0



Domain of the equation: 2)t^2!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

(+3/2)t^2-11t+14=0

We add all the numbers together, and all the variables

-11t+(+3/2)t^2+14=0

We multiply all the terms by the denominator


-11t*2)t^2+(+14*2)t^2+3=0

We add all the numbers together, and all the variables

-11t*2)t^2+28t^2+3=0

Wy multiply elements

-22t^2=0

a = -22; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-22)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{-44}=0$

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